Question 1004079

sqrt(4-3x)-2= sqrt (8+x)


{{{(sqrt(4-3x) -2)^2 = (sqrt(8+x))^2}}}


{{{4-3x -2(sqrt(4-3x))*2+4 = 8+x}}}



{{{8-3x -4(sqrt(4-3x)) = 8+x}}}


{{{4(sqrt(4-3x)) = 8-3x-8-x}}}


{{{4(sqrt(4-3x)) = -4x}}}

/4

{{{(sqrt(4-3x)) = -x}}}


square both sides

4-3x = x^2

x^2+3x-4=0

x^2+4x-x-4=0

x(x+4)-1(x+4)=0

(x+4)(x-1)=0

x=-4 OR 1