Question 1004017
From 6sin^2(θ) − 7cos^2(θ) = 0
6sin^2(θ) − 7(1 - sin^2(θ) = 0
13sin^2(θ) − 7 = 0
13sin^2(θ) = 7
sin^2(θ) = 7/13
sin(θ) = +/- sqrt(7/13) = +/- .738
so that 
θ = 47.2, 132.8, 227.2, 312.8 degrees