Question 1003882
*[tex \large \frac{x}{x-5} + \frac{4}{x+5} = \frac{50}{x^2-25}]


First, multiply both sides by *[tex \large x^2 - 25] (which is equal to (x-5)(x+5). Note that many LHS terms cancel.


*[tex \large x(x+5) + 4(x-5) = 50]


Solve the quadratic.