Question 1003886
totally stumped on how to solve this problem:


y-1/y^2-3y-4    =  1/y-4    -   1/y+1

(y-1)/(y-4)(y+1) = ((y+1)-(y-4))/(y+1)(y-4)

=> (y-1) = (y+1-y+4)

y-1 = 5
y=6