Question 85838
{{{(sqrt(2x+5))}}}=5
{{{((sqrt(2x+5))^2)}}}={{{(5^2)}}} [square both sides to get rid of the radical sign]
.
2x+5=25
2x+5-5=25-5 [solve for the x-term]
2x=20
2x/2=20/2
x=10
.
Checking:
{{{(sqrt(2x+5))}}}=5
{{{(sqrt(2(10)+5))}}}=5
{{{(sqrt(25))}}}=5
5=5 [checks out]