Question 1003838
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{{{64x^3}}} - {{{27y^6}}} = {{{(4x)^3}}} - {{{(3y^2)^3}}}.


Next apply the formula  {{{a^3 - b^3}}} = {{{(a-b)*(a^2 + ab + b^2)}}}


with  {{{a}}} = {{{4x}}}  and  {{{b}}} = {{{3y^2}}}.