Question 1003808
Let f be a function such that f(-1) = 3 and f(2) = -4. The
coordinates of two points on the graph of y = 3f(-x) - 2
are ?
<pre>
We just have to be very careful with our signs:

Start with

{{{y = 3f(-x^"") - 2}}}

Substitute 1 for x

{{{y = 3f(-(1)^"") - 2}}}

{{{y = 3f(-1) - 2}}}

Substitute 3 for f(-1) since that is given

{{{y = 3(3) - 2}}}

{{{y = 9 - 2}}}

{{{y = 7}}}

So one point is (x,y) = (1,7)

Again start with

{{{y = 3f(-x^"") - 2}}}

Substitute -2 for x

{{{y = 3f(-(-2)^"") - 2}}}

{{{y = 3f(2) - 2}}}

Substitute -4 for f(2) since that is given

{{{y = 3(-4) - 2}}}

{{{y = -12 - 2}}}

{{{y = -14}}}

So another point is (x,y) = (-2,-14)

Edwin</pre>