Question 1003768
(3x)^(1 + log of x base 3) = 3
note that (3x)^(1 + log of x base 3) = 3 * x^(2 + (log x  / log 3)
note that log is natural logarithm
 3 * x^(2 + (log x  / log 3) = 3
divide both sides of = by 3
x^(2 + (log x  / log 3) = 1
take natural log of both sides of =
log(x)(2 + (log x  / log 3) = 0
now write left side of = as a fraction with common denominator log(3)
log(x)(2log(3)+log(x)) / log(3) = 0
multiply both sides of = by log(3)
log(x)(2log(3)+log(x)) = 0
there are two solutions
1) log(x) = 0
x = 1
2) 2log(3) + log(x) = 0
log(x) = -2log(3)
note -2log(3) = log(1/(3^2)) = log(1/9)
x = 1/9