Question 1003747
Let the length be l and the width be b.
Now, l= 2b +2 is given.

According to pythagoras theorem
(diagonal)^2= l^2 + b^2
so, 13*13= l*l + b*b;
 169= (2b+2)(2b+2) + b*b;
 169= 4(b+1)(b+1) + b^2;
 169= 4(b^2 + 2b + 1) + b^2;
 169= 5b^2 + 8b + 4;
 5b^2 + 8b - 165 = 0;
 5b^2 + 33b - 25b -165 =0;
 b(5b +33) - 5(5b + 33) = 0;
 (b - 5)*(5b + 33) = 0;
  so, b=5;
 l= 2b+2 = 10+2= 12;

so, l=12, b=5;