Question 1003745
Unknown point (x,y),


{{{sqrt((x+2)^2+y^2)=4}}}
and
{{{sqrt((x-2)^2+y^2)=4}}}


Can you work with those two equations, and find the common points, their intersection  (either or both of them)?


Start with the first equation, and solve y^2 in terms of ....
find that {{{y^2=16-(x+2)^2}}}.
Substitute this into the other equation.
{{{(x-2)^2+y^2=16}}}
{{{(x-2)^2+(16-(x+2)^2)=16}}}
and a few more steps to find
{{{highlight(x=0)}}}.


Go back to either equation of the system, use this found x=0, and solve for y.


You should find two possible y values.  Not surprising that the two points will be on the vertical y-axis for x=0.