Question 1003627
m = numbr of midsized cars.
f = number of full sized cars.


m + f = 75
10,000m + 15,000f = 1,000,000


you need to solve both these equations simultaneously to get a solution that is common to both.


first equation says total number of midsize and fullsize cars is equal to 75.


second equation says total amount of money paid for midsize cars and full size cars is 1,000,000.


multiply both sides of the first equation by 10,000 and bring down the second equation unchanged to get:


10,000m + 10,000f = 750,000
10,000m + 15,000f = 1,000,000


subtract the first equation form the second equation to get:


5,000f = 250,000


divide both sides of this equation by 5,000 to get:


f = 50


since m + f = 75, then m = 25


you have m = 25 and f = 50


25 + 50 = 75
10,000 * 25 = 250,000
15,000 * 50 = 750,000
total = 1,000,000


solution is:


she could stock 25 midsize cars and 50 full size cars.