Question 1003675
I have a problem here that states. There are two buildings (I will call them "nearby building" and "skyscraper") and need to find the height of both buildings. 
-What we are told is the distance between them is 75m.
-The angle of elevation from the base of the "nearby building" to the top of the "skyscraper" is 54 degrees.
-The angle of elevation from the roof of the "nearby building" to the top of the "skyscraper" is 45 degrees.

Here is the solution I have came up with, knowing the angle from the "nearby building" to the top of the "skyscraper" and considering the other angle is 36. I need to then find the tan(36).

tan36=75/x
x= 75/tan36
x= 103.2
So the skyscraper would be 103.2 meters tall

For the "nearby building" we would do the same
tan45=75/x
x=75/tan45
x=75
Then find the difference 103.2-75=28.2
The nearby building would then be 28.2 meters tall

I wish I could include the graphic I drew to explain it visually, sorry if I didn't word this well enough to understand. We are also told to round to the nearest tenth.
<pre>*[illustration Heights_Buildings].
Height of skyscraper: {{{75 * tan 54^o}}} = 103.2286 m &#8776; {{{highlight_green(103.2)}}} m
Difference in heights of both buildings: {{{75 * tan 45^o}}} = 75 m
Height of shorter building: 103.2286 - 75 = 28.2286 &#8776; {{{highlight_green(28.2)}}} m