Question 1003673
The product of two consecutive positive integers is 119 more than the next integers. What is the largest of the three integers?
1st:x-1
2nd:x
3rd:x+1
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Equation:
(x-1)x = x+1+119
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x^2 - x = x + 120
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x^2 - 2x - 120 = 0
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(x-12)(x+10) = 0
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x = 12
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Largest = x+1 = 13

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Cheers,
Stan H.

11 
13
14
9