Question 1003630
Those are two of the many possible arrangements, and you correctly calculated the perimeter.
Th area is 60 square meters for all arrangements of course,
because the gardener is laying down 60 slabs, each with a 1 square meter surface area.


To find them all, we must list them systematically.
The width and length of the rectangle (in meters or number of slabs) must divide {{{60}}} evenly.
So {{{width}}} and {{{length}}} {would be factors of {{{60}}} such that
{{{width*length=60}}}<-->{{{length=60/width}}} .
We look for small factors of {{{60}}} that could be the width, and we fond the corresponding length.
We try 1, 2, 3, etc, in order, and see if each one is a factor.
It could be:
{{{width=1}}} , and {{{length=60/1=60}}} ,
{{{width=2}}} , and {{{length=60/2=30}}} ,
{{{width=3}}} , and {{{length=60/3=20}}} ,
{{{width=4}}} , and {{{length=60/4=15}}} ,
{{{width=5}}} , and {{{length=60/5=12}}} ,
{{{width=6}}} , and {{{length=60/6=10}}} .
So we found {{{6}}} different ways to arrange those {{{60}}} slabs in a rectangle.

{{{7}}} , {{{8}}} , and {{{9}}} are not factors (they do not divide {{{60}}} evenly).
{{{10}}} is a factor, but we cannot say that {{{width=10}}} ,
because we had already found a rectangle with {{{width=6}}} , and {{{length=10}}} above,
and since the side measuring {{{10}}} was the longest side,
it is a length not a width.