Question 1003638
Find three consecutive odd integers such that three times the first minus the second is one more than the third
<pre>Let the 1<sup>st</sup> integer be F
Then 2<sup>nd</sup> and 3<sup>rd</sup> are: F + 2, and F + 4, respectively
We then get: 3F - (F + 2) = F + 4 + 1
Solve for F, the 1<sup>st</sup> integer (Make sure that this is AN ODD INTEGER)
Add 2 to the 1<sup>st</sup> integer to get the 2<sup>nd</sup>
Add 4 to the 1<sup>st</sup> to get the 3<sup>rd</sup>