Question 1003638
Before finding them,  2n+1, 2n+3, 2n+5.


The description means  {{{3(2n+1)-(2n+3)=1+(2n+5)}}}.


Solve for n and evaluate the three consecutive odd integers.


{{{6n+3-2n-3=1+2n+5}}}


{{{6n-2n=2n+5+1}}}


{{{4n-2n=6}}}


{{{2n=6}}}


{{{highlight(n=3)}}}


The integers are 7, 9, 11.