Question 85826
evaluate these exponetials (that is, express them in cartesian and/or polar form):

1.)  e^1+ipi     --       2.)  e^ipi/2      --     3.)  e^e^Inpi+ipi/2 

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Formula: e^(a+bi) = (e^a)(cosb + isinb)
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Your Problems:
1. e^(1+ipi) = 
Polar form: e(cospi + isinpi) 
Cartesian form: (-e,0)
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2. e^(0 + i(pi/2)) =
Polar form: e^0(cos(pi/2)+isin(pi/2)
Cartesian form: (0,1)
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3. Did you mean what you posted?
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Cheers,
Stan H.