Question 85834
Y=2(x-1)^2+3

Find x-intercepts.  
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Let y= 0 and solve for x:
2(x-1)^2+3 = 0
(x-1)^2 = -3/2
Since the square equals a negative value
x-1 is a complex number (not a Real Number).
So the x-intercepts are complex.
The graph of your function does not cross the x-axis.
There are no x-intercepts.
{{{graph(400,300,-10,10,-10,10,2(x-1)^2+3)}}}
Cheers,
Stan H.