Question 1003438
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ \frac{2}{3}x^3\ -\ 5x^2\ +\ 12x\ -\ 7]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\text{d}y}{\text{d}x}\ =\ 2x^2\ -\ 10x\ +\ 12]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\text{d}^2y}{\text{d}x^2}\ =\ 4x\ -\ 10]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \