Question 1003543
The perimeter of a rectangle is 30 inches , and its area is 54 square inches. Find the length of the longest side of the rectangle.
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P = 2(Length + Width)
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Length + Width = 15 inches
Length * Width = 54 in^2
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L + W = 15
L*W = 54
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Substitute for "L" and solve for "W":
(15-W)*W = 54
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-W^2 + 15W - 54 = 0
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W^2 - 15W + 54 = 0
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W = 6 or W = 9
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If Width = 6, Length = 9
If Width = 9, Length = 6
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Cheers,
Stan H.
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