Question 1003534
.
Find the exact solution to the equation in the interval [3π/2, 5π/2]: 
sin (t) = (-squareroot3/2).
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sin(t) = {{{-sqrt(3)/2}}}.


The solutions in the interval  [0, {{{2pi}}})  are


t = {{{4pi/3}}}  and  {{{(5pi)/3}}}. 


Of these two only one is in the interval  [{{{3pi/2}}}, {{{5pi/2}}}].


It is  t = {{{(5pi)/3}}}.

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{{{graph( 330, 330, 4.71, 7.85, -1.5, 1.5,
          sin(x), -0.866
)}}}


Plot &nbsp;y = sin(x)  &nbsp;and &nbsp;y = -{{{sqrt(3)/2}}}
in the interval &nbsp;[{{{3pi/2}}}, {{{5pi/2}}}].

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