Question 1003477
Ho: m=f with hours studied
Ha: m NE f
alpha=0.05
test statistic t df=12
critical value |t|>2.1788
t=(xbar1-xbar2)-(mu1-mu2)/sqrt {(s1^2/n1)+(s2^2/n2)}
You should get means of samples of 19 and 21.29
s1=6.11
s2=4.72
n1=n2=7
t value is-0.783
p=0.45
Ho is not rejected, and this means there is insufficient evidence here to reject the null hypothesis that the hours studied are different.