<PRE><B>Question 1003334</B>
if an object is thrown downward with an initial velocity of Vo. Then the distance it travels is given by S=-4.9t^2+Vot. an object thrown downward from an airplane 500m from the ground with an initial velocity of 8 m/sec. how long does it take for an object to reach the ground? 
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S(t) = -4.9t^2 - 8t + 500
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Solve:: -4.9t^2 - 8t + 500 = 0
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t = 9.36 seconds
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Cheers,
Stan H.
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