Question 1003157
log(base of 6)(1/z^3) = log(base of 6)(z^-3) = -3*log(base of 6)(z)
log(4x^2)y = log(4) + 2*log(x) + log(y)
4[ln z + ln(z + 5)] - 2 ln (z - 5) = ln[(z(z+5))^4/((z-5)^2)]