Question 85806
9y^4 over 6y divided by y^2 over 3 

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[9y^4/6y] / [y^2/3]

Invert the denominator and multiply the results:

= [9y^4/6y] * [3/y^2]

Cancel factors that are common to a numerator and a denominator:

= [3y^3/2] * [3/y^2]

= [3y/2] * [3/1]

= 9y/2

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Cheers,
Stan H.