Question 1002899
the man dies at x years of age.
he has his first child at 1/2 * x years of age.
he has his second child at 2/3 * x years of age.


when the man dies, his first child is x - 1/2 * x = 1/2 * x years of age.
when the man dies, his second child is x - 2/3 * x = 1/3 * x years of age.


the sum of the children's ages when the man dies is 60.


you get:


1/2 * x + 1/3 * x = 60


multiply both sides of this equation by 6 to get:


3 * x + 2 * x = 6 * 60 which becomes:


5 * x = 360


divide both sides of this equaton by 5 to get:


x = 72


the man dies when he is 72 years of age.


his first child is born when he is 1/2 * 72 = 36 years old.
his second child is born when he is 2/3 * 72 = 48 years old.


when he dies, his first child is 72 - 36 = 36 years old.
when he dies, his second child is 72 - 48 = 24 years old.


when he dies, the sum of his children's ages is 36 + 24 = 60.


solution is confirmed to be correct.


your solution is that the man dies when he is 72 years old.