Question 1002871
Find two numbers given that their sum is 48 and the smaller number is equal to 1/5 of the larger number. 


let one number be x
other be y  (x>y)

x+y =48...................(1)

y= (1/5) x

5y=x

x+y =48

substitute x
5y+y =48
6y=48
y =8

Now x+y =48
x+8=48

x=40

40, 8