Question 1002802
Let {{{ n }}} = number of nickels
Let {{{ d }}} = number of dimes
Let {{{ q }}} = number of quarters
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(1) {{{ n + d + q = 14 }}}
(2) {{{ 5n = 10d }}}
(3) {{{ 5n + 10d + 25q = 130 }}} ( in cents )
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(2) {{{ n = 2d }}}
(1) {{{ 2d + d + q = 14 }}}
(1) {{{ 3d + q = 14 }}}
(1) {{{ q = -3d + 14 }}}
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(3) {{{ 5n + 10d + 25q = 130 }}}
(3) {{{ 5*2d + 10d + 25*( -3d + 14 ) = 130 }}}
(3) {{{ 10d + 10d - 75d + 350 = 130 }}}
(3) {{{ -55d = -220 }}}
(3) {{{ d = 4 }}}
and
(2) {{{ n = 2d }}}
(2) {{{ n = 2*4 }}}
(2) {{{ n = 8 }}}
and
(1) {{{ q = -3d + 14 }}}
(1) {{{ q = -3*4 + 14 }}}
(1) {{{ q = 14 - 12 }}}
(1) {{{ q = 2 }}}
There are 8 nickels
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check answer:
(3) {{{ 5n + 10d + 25q = 130 }}}
(3) {{{ 5*8 + 10*4 + 25*2 = 130 }}}
(3) {{{ 40 + 40 + 50 = 130 }}}
(3) {{{ 130 = 130 }}}