<PRE><B>Question 1002808</B>
What are the dimensions of the first rectangle? if in a certain rectangle,the sum of the length and the width is 14 (measured in cm). 
length = x
width = 14-x
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A second rectangle is 5 times as long as the first, and 3 times as wide.
length = 5x
width = 3(14-x) = 42-3x
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The perimeter of the second rectangle is 91 
2[5x + 42-3x] = 91
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2[2x+42] = 91
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4x + 84 = 91
4x = 7
x = 7/4 (length of the 1st rectangle)
14-x = 14-(7/4) = 12 1/4 (width of the 1st rectangle)
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Cheers,
Stan H.
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