Question 1002703
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Since *[tex \Large x] is not represented in the equation, the value of the *[tex \Large x] coordinate can be anything you want it to be, and no matter what value you choose for *[tex \Large x], *[tex \Large y] will always take on the indicated value, in this case *[tex \Large -5], so a point on this line is (<i>anything you like</i>, -5)


The slope of such a line is found by using the slope formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m\ =\ \frac{y_1\ -\ y_2}{x_1\ -\ x_2} ]


In this case:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{-5\ -\ (-5)}{x_1\ -\ x_2} ]


And no matter what values you choose for *[tex \Large x_1] and *[tex \Large x_2] (so long as *[tex \Large x_1\ \not =\ x_2]), the value of the slope is 0.


For the visual learner, this is a horizontal line.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
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