Question 12191
{{{(2+i)/(3+4i)*(3-4i)/(3-4i)}}}
{{{(6-8i+3i-4i^2)/(9-16i^2)}}}
{{{(6-5i-4i^2)/(9-16*(-1))}}}               -------> (Remember: i^2 = -1)
{{{(6-5i-4*(-1))/(9-16*(-1))}}}
{{{(6+4-5i)/(9+16)}}}
{{{(10-5i)/25}}}
{{{5*(2-i)/25}}}
{{{(2-i)/5}}}

OK