Question 1002730
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If *[tex \Large v] varies jointly as *[tex \Large h] and the square of *[tex \Large g], then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ v\ =\ khg^2]


Substitute the values of the initial condition, solve for *[tex \Large k].  Once you have *[tex \Large k] then you have a formula to solve for any one of the variables given the other two.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
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