Question 1002611
Find the sum.

5/m^2n^2   +    m/n
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Find a common denominator. m^2n^2 will work.
{{{5/m^2n^2   +    m/n = 5/m^2n^2   +    (m/n)*(m^2n/m^2n)}}}
= {{{5/m^2n^2   +    m^3n/m^2n^2}}}
= {{{(m^n + 5)/(m^2n^2)}}}