Question 1002510
{{{ax^2+bx+c=y}}}

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{{{system(a*0+b*0+c=6,a*4+b*2+c=14,a*16+b*4+c=-2)}}}


{{{system(highlight(c=6),4a+2b+c=14,16a+4b+c=-2)}}}


{{{system(4a+2b+6=14,16a+4b+6=-2)}}}


{{{system(4a+2b=8,16a+4b=-8)}}}


{{{system(2a+b=4,4a+b=-2)}}}--------R


{{{(4a+b)-(2a+b)=-2-4}}}


{{{2a=-6}}}


{{{highlight(a=-3)}}}


Return to R,
{{{b=4-2a}}}
{{{b=4-2(-3)}}}
{{{highlight(b=10)}}}


Put the coefficient found into the general form equation shown at top of this solution posting.