Question 1002248
Pythagorean Theorem :D

Since tangent equals opposite/adjacent we know

opposite=1

adjacent=3

Use the Pythagorean Theorem to find the hypotenuse a^2+b^2=c^2

1^2+3^2=c^2

1+9=c^2

10=c^2

sqrt10=c

hypotenuse=sqrt10

opposite=1

adjacent=3

Sine is opposite over hypotenuse so

sine=1/sqrt10....but most teachers hate a root in the demonatoer so mutplily by 
sqrt10/sqrt10 ... this is legal since it equals one

so sine=sqrt10/10

csc is just the inverse of sine so

csc=sqrt10

cosine adjacent over hypotenuse

cosine=3/sqrt10 again root on the bottom so

cosine=3sqrt10/10

sec is the inverse of cosine so 

sec=sqrt10/3

inverse of tangent is cotangent so

cot=3


Hope that helps!