Question 1002414
You've invested $9000 between two accounts paying 7% and 9% annual interest. If the total interest earned for the year was $730, how much was invested at each rate?
let x=amt invested at the 7% interest rate
9000-x=amt invested at the 9% interest rate
.07x+.09(9000-x=730
.07x+810-.09x=730
.02x=80
x=4000
9000-x=5000
amt invested at the 7% interest rate=$4000
amt invested at the 9% interest rate=$5000