Question 1002353
 melisa came to the bank to make a deposit of loose change in her checking account.
Those coins being quarters, dimes and pennies.
let q = no. of quarters
let d = no. of dime
let p = no. of pennies
:
Write an equation for each statement
:
 The total she deposited was $10.19.
.25q + .10d + .01p = 10.19
:
 There were 71 coins in total.
q + d + p = 71
:
 The amount of pennies was twice the amount of dimes.
p = 2d
:
in the two above equations replace p with 2d
.25q + .10d + .01(2d) = 10.19
.25q + .12d = 10.19
and
q + d + 2d = 71
q + 3d = 71
q = -3d + 71
:
Replace q with (-3d+71) in .25q + .12d = 10.19
.25(-3d+71) + .12d = 10.19
-.75d + 17.75 + .12d = 10.19
-.75d + .12d = 10.19 - 17.75
-.63d = -7.56
d = -7.56/-.63
d = +12 dimes
Find the quarters
q = -3(12) + 71
q = 35 quarters
"The amount of pennies was twice the amount of dimes."
p = 2(12)
p = 24 pennies
:
Check to see if all this adds up
.01(24) + .10(12) + .25(35) =
.24 + 1.20 + 8.75 = 10.19
:
 How many of each coin is there? 24 pennies, 12 dimes and 35 quarters