Question 1002372
vertex form is y=a(x-h)^2 + k, where h and k are the vertex coordinates.
So, we have y=a(x+3^2) +2.  Note that the sign of x changed.
Now we need a point to solve for a.
-8=a(-5+3)^2 + 2
-8=4a+2
4a=-10
a=-2.5
y= -2.5(x+3)^2+2
{{{graph(300,200,-10,10,-10,10,-2.5(x+3)^2+2)}}}