<PRE><B>Question 1002254</B>
What is the exact solution of the equation 
log4 = 1+log(x+1)

solution    
  we know log10=1   substitute  1= log10

log4 = 1+log(x+1)
log4= log10 +log(x+1)   by using law log m +logn =log (mn)
log 4= log[10(x+1)]    by anti log  
4=10(x+1)
4/10 = x+1
0.4 =x+1
x=0.4-1=-0.6</PRE>