Question 1002256
Choose either log base e or log base ten.  Your choice.


{{{e^(x+2) = 10^x}}}


{{{ln(e^(x+2))=ln(10^x)}}}


{{{(x+2)ln(e)=x*ln(10)}}}


{{{(x+2)*1=x*ln(10)}}}


{{{x+2=x*ln(10)}}}
{{{x*ln(10)-x=2}}}
{{{x(ln(10)-1)=2}}}


{{{highlight(x=2/(ln(10)-1))}}}