Question 1002262
Two cards are drawn without replacement from the ordinary
deck, find the probability that the second is not a face 
card given that the first is a face card.
<pre>

A deck of 52 cards contains 12 face cards, and 40 non-face 
cards. 

<font color = "red">
 
A&#9829;   2&#9829;   3&#9829;   4&#9829;   5&#9829;   6&#9829;   7&#9829;   8&#9829;  9&#9829;  10&#9829;  J&#9829;  Q&#9829;  K&#9829; 
A&#9830;   2&#9830;   3&#9830;   4&#9830;   5&#9830;   6&#9830;   7&#9830;   8&#9830;  9&#9830;  10&#9830;  J&#9830;  Q&#9830;  K&#9830;</font>
A&#9824;   2&#9824;   3&#9824;   4&#9824;   5&#9824;   6&#9824;   7&#9824;   8&#9824;  9&#9824;  10&#9824;  J&#9824;  Q&#9824;  K&#9824;  
A&#9827;   2&#9827;   3&#9827;   4&#9827;   5&#9827;   6&#9827;   7&#9827;   8&#9827;  9&#9827;  10&#9827;  J&#9827;  Q&#9827;  K&#9827; 

Since we are given that the first card has been drawn and it was a
face card and we are not going to replace it before drawing a second
card, then

we have a 51-card deck with only 11 face cards and still 40 non-face 
cards.

So the probability is 40 ways out of 51.

Answer 40/51

Edwin</pre>