Question 1002148
{{{log(9,(log(5,x)))=1/2}}}........change to the base {{{10}}} given {{{log(5,x)}}}


{{{log(9,(log(x)/log(5)))=1/2}}}.......change to the base {{{10}}} again


{{{log((log(x)/log(5)))/log(9)=1/2}}}


{{{log((log(x)/log(5)))=(1/2)log(9)}}}


{{{log((log(x)/log(5)))=log(9^(1/2))}}}


{{{log((log(x)/log(5)))=log(sqrt(9))}}}


{{{log((log(x)/log(5)))=log(3)}}}...if log same, we have


{{{log(x)/log(5)=3}}}


{{{log(x)=3log(5)}}}


{{{log(x)=log(5^3)}}}


{{{log(x)=log(125)}}}...if log same, we have


{{{x=125}}}