Question 1002068
Hi dear,
let the interger be x,x+1,x+2,andx+3,.
since,the sum of the first three is 54 more than the fourth,
Then,
x+x+1+x+2=x+3+54
3x+3=x+57
2x=57-3
2x=54
x=27
The consecutive intergers are:27,28,29,and 30 
OR
-27,-28,-29 and -30
HOPE THIS HELPS?