Question 1001955


Tobias starts out jogging from Dauntless Headquarters at 6:00 a.m. at a speed of 4 mi/h. Twelve minutes later, Tris starts out from Dauntless Headquarters and follows the same route. At what constant rate in miles per hour must Tris run to catch Tobias at 6:42 a.m.? Put answer into nearest tenth decimal
<pre>Distance Tobias has traveled in 42 (6:00 a.m. – 6:42 a.m.) minutes is: {{{4(42/60)}}}, or 2.8 miles
Time Tris takes to travel 2.8 miles = 30 (6:12 a.m. – 6:42 a.m.) minutes, or {{{1/2}}} hour
Speed at which Tris needs to travel to catch Tobias at 6:42 a.m. = {{{2.8/(1/2)}}}, or 2.8 * 2, or {{{highlight_green(5.6)}}} mph