Question 1001962

{{{2x- y = -8}}}
{{{x + 2y = 10}}}
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write both in slope-intercept form {{{y=ax+b}}} where {{{a}}} is a slope and {{{b}}} is y-intercept

recall that:  
parallel lines have {{{same}}} slope
perpendicular lines have slopes negative reciprocal of each other

{{{2x+8 = y}}}=>{{{a=2}}}
{{{y =-(1/2)x+ 5}}}=>{{{a=-(1/2)}}}
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since {{{a=2}}} is  negative reciprocal of {{{a=-(1/2)}}}, your lines are perpendicular

here is a graph:

{{{ graph( 600, 600, -10, 10, -10, 10, -(1/2)x+ 5, 2x+8) }}}

and, your answer is: B.	{{{perpendicular}}}