Question 1001880
<font face="Times New Roman" size="+2">


The diagonals of a rhombus are perpendicular, hence the two diagonals and the sides of the rhombus create four congruent right triangles where each side of the rhombus is the hypotenuse of one of the triangles.  Since you have sides of 10 (hypotenuse) and one-half of a diagonal is 8 (one leg), you can calculate the measure of one-half of the other diagonal using Pythagoras (or by recognizing a 3-4-5 right triangle).  The area is the half of one diagonal times half of the other diagonal times 2.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \