<PRE><B>Question 1001816</B>
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Since the designation of the people and the toys is arbitrary, you can lay it out thusly without loss of generality:


A contributed to Toy #1 through Toy #10


B contributed to Toy #1 through Toy #10


C contributed to Toy #3 through Toy #10  (total of 8 toys)


D contributed to Toy #9 through Toy #10  (total of 2 toys)


So I count a total of 30 participation shares, 10 for A, 10 for B, 8 for C, and 2 for D.


Hence the percentages are *[tex \Large 33\frac{1}{3}%] each for A and B, *[tex \Large 26\frac{2}{3}%] for C and *[tex \Large 6\frac{2}{3}%] for D.



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  </PRE>