Question 1001849
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \mu\ =\ \sum\,x\cdot P(x)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sigma^2\ =\ \sum\,\left(x^2\cdot P(x)\right)\ -\ \mu^2]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \