Question 1001649
Graph linear inequalities

{{{y>-(3/5)x+2}}}

first make it equal, {{{y=-(3/5)x+2}}} find two points (best is to find x and y-intercept)

x-intercept: set {{{y=0}}}

{{{0=-(3/5)x+2}}}

{{{(3/5)x=2}}}

{{{3x=2*5}}}

{{{x=10/3}}}

y-intercept: set {{{x=0}}}

{{{y=-(3/5)0+2}}}

{{{y=2}}}

so, points that lie on the line are:

({{{10/3}}},{{{0}}}) and ({{{0}}},{{{2}}})

plot these points, draw dashed line through, the line is not part of solution because you need {{{y>-(3/5)x+2}}}

{{{drawing( 600, 600, -10, 10, -10, 10,
circle(10/3,0,.12),circle(0,2,.12),
 graph( 600, 600, -10, 10, -10, 10, -(3/5)x+2)) }}}


now shade the area above the line


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(10/3,0,.12),circle(0,2,.12),
 graph( 600, 600, -10, 10, -10, 10, y>-(3/5)x+2)) }}}