Question 1001770
Calculus.
First graph the equations so you know what you're dealing with and can determine the limits of integration.
*[illustration DS.JPG].
It looks like the line is above the parabola between {{{x=-2}}} and {{{x=1}}} so that's the area you're interested in (?).
So then,
{{{A=int(((2-x)-x^2),dx,x=-2,1)}}}
{{{A=2x-x^2/2-x^3/3+C}}}
Evaluating between the limits,
{{{A= 2(1)-(1)^2/2-(1)^3/3-(2(-2)-(-2)^2/2-(-2)^3/3) }}}
{{{A=9/2}}}